(x+(1/x))^2-14(x+(1/x))=72

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Solution for (x+(1/x))^2-14(x+(1/x))=72 equation: 



(x+(1/x))^2-14(x+(1/x))=72

We move all terms to the left:

(x+(1/x))^2-14(x+(1/x))-(72)=0



Domain of the equation: x))^2!=0

x!=0/1

x!=0

x∈R





Domain of the equation: x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(x+(+1/x))^2-14(x+(+1/x))-72=0

We calculate fractions


2x/x)^2*x)))+(-14(x+(+x))^2)/x)^2*x)))-72=0

We can not solve this equation

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